SOLUTION: Please find the value of 'k' so that the line passes through (-2,k) and (2k,2) and has a slope of -0.25 THANK YOU

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Please find the value of 'k' so that the line passes through (-2,k) and (2k,2) and has a slope of -0.25 THANK YOU      Log On


   

Question 229916: Please find the value of 'k' so that the line passes through (-2,k) and (2k,2) and has a slope of -0.25
THANK YOU
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Please find the value of 'k' so that the line passes through (-2,k) and (2k,2)
and has a slope of -0.25
:
Use the slope formula, m = %28y2-y1%29%2F%28x2-x1%29 ; assign values as follows
x1=-2; y1=k
x2=2k; y2=2
m = -.25
:
-.25 =%282+-+k%29%2F%282k+-+%28-2%29%29
:
-.25 = %282+-+k%29%2F%282k+%2B+2%29
Multiply both sides by (2k+2)
;
-.25(2k + 2) = 2 - k
;
-.5k - .5 = 2 - k
:
-.5k + k = 2 + .5
:
.5k = 2.5
Multiply both sides by 2
k = 5
;
;
See if that works in the slope equation
%282+-+k%29%2F%282k+%2B+2%29 =
%282+-+5%29%2F%2810+%2B+2%29 = %28-3%29%2F%2812%29 = -.25