SOLUTION: What is the hang time of a basketball player with a 35 inch reach?

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: What is the hang time of a basketball player with a 35 inch reach?      Log On


   

Question 214935: What is the hang time of a basketball player with a 35 inch reach?
Answer by drj(1380) About Me  (Show Source):
You can put this solution on YOUR website!
What is the hang time of a basketball player with a 35 inch reach?

Step 1. The equation is given as h=g%2At%5E2%2F2 where h is the height, g is the gravity given as 32 ft/sec^2 and t is the time to travel a given height.

Step 2. The hang time is 2*t (t to go up and anther t to go down)

Step 3. Solve for t in Step 1 as follows:

h=g%2At%5E2%2F2

2h%2Fg=t%5E2 where we multiplied by 2/g to both sides of the equation

t=sqrt%282h%2Fg%29 where we took the square root to both sides of the equation and selected the positive time.

t=sqrt%282%2A35%2F%2832%2A12%29%29 where 12 inch = 1 feet or 35 inches is 35/12 feet

t=0.18229

2t=0.3646

Step 4. Hang time is 0.3646 seconds.

I hope the above steps were helpful.

For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.

Good luck in your studies!

Respectfully,
Dr J