SOLUTION: Tell whether the graph opens up or down. Find the coordinates of the vertex. Write an equation of the axis of symmetry. y=-9x(to the 2nd power) I don't know how to type to the 2

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Tell whether the graph opens up or down. Find the coordinates of the vertex. Write an equation of the axis of symmetry. y=-9x(to the 2nd power) I don't know how to type to the 2      Log On


   



Question 2128: Tell whether the graph opens up or down. Find the coordinates of the vertex. Write an equation of the axis of symmetry.
y=-9x(to the 2nd power) I don't know how to type to the 2nd power on the computer

Answer by matthew_sessoms(39) About Me  (Show Source):
You can put this solution on YOUR website!
y=-9x%5E2


Anytime the x^2 term is a negative it is going to open down. Anytime the x^2 term is positive it is going to open up.
So, this parabola opens down.


Since there is only 1 term, which is 9x^2, we really can't complete the square. However, we could say y=9%28x%2B0%29%5E2%2B0. This is in the form of y=a(x-h)^2+k, where (h,k) is the vertex and x=h is the axis of symmetry.

So, (0,0) is the vertex...
x=0 is the axis of symmetry.



Here is the graph to prove my statements...
graph%28+400%2C+200%2C+-.625%2C+.625%2C+-.625%2C+.625%2C+-9+x%5E2%29
MS