SOLUTION: Is this correct? {{{3^2-5x+4 = 0}}} x = 25 +-Square root -23i over 6?

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Question 210149: Is this correct?
3%5E2-5x%2B4+=+0
x = 25 +-Square root -23i over 6?
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
I'm assuming you meant to write 3x%5E2-5x%2B4+=+0




3x%5E2-5x%2B4=0 Start with the given equation.


Notice that the quadratic 3x%5E2-5x%2B4 is in the form of Ax%5E2%2BBx%2BC where A=3, B=-5, and C=4


Let's use the quadratic formula to solve for "x":


x+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29 Start with the quadratic formula


x+=+%28-%28-5%29+%2B-+sqrt%28+%28-5%29%5E2-4%283%29%284%29+%29%29%2F%282%283%29%29 Plug in A=3, B=-5, and C=4


x+=+%285+%2B-+sqrt%28+%28-5%29%5E2-4%283%29%284%29+%29%29%2F%282%283%29%29 Negate -5 to get 5.


x+=+%285+%2B-+sqrt%28+25-4%283%29%284%29+%29%29%2F%282%283%29%29 Square -5 to get 25.


x+=+%285+%2B-+sqrt%28+25-48+%29%29%2F%282%283%29%29 Multiply 4%283%29%284%29 to get 48


x+=+%285+%2B-+sqrt%28+-23+%29%29%2F%282%283%29%29 Subtract 48 from 25 to get -23


x+=+%285+%2B-+sqrt%28+-23+%29%29%2F%286%29 Multiply 2 and 3 to get 6.


x+=+%285+%2B-+i%2Asqrt%2823%29%29%2F%286%29 Simplify the square root


x+=+%285%2Bi%2Asqrt%2823%29%29%2F%286%29 or x+=+%285-i%2Asqrt%2823%29%29%2F%286%29 Break up the expression.


So the solutions are x+=+%285%2Bi%2Asqrt%2823%29%29%2F%286%29 or x+=+%285-i%2Asqrt%2823%29%29%2F%286%29