SOLUTION: solve by using quadratic formula (((6x2+3x-18=0))) my answer is x=-2 3/2 -b+- sq root of b^2-4ac/2a a=6 b=3 c=18 so -3+-sqrt(9-4(6)l-18/12 -3t-sqrt9441)/12 -3+-21/12 and x=

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Question 204725: solve by using quadratic formula (((6x2+3x-18=0)))
my answer is x=-2 3/2
-b+- sq root of b^2-4ac/2a
a=6
b=3
c=18
so -3+-sqrt(9-4(6)l-18/12
-3t-sqrt9441)/12
-3+-21/12 and x=-3-21/12
x=-3+21/12 and x=-3-21/12
x=18/12=3/2 and x=-2
this is how I came up with this answer is this right?

Found 2 solutions by Earlsdon, Alan3354:
Answer by Earlsdon(6294) (Show Source):
You can put this solution on YOUR website!
Youre answers are perfect!
Congratulations!

Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website!
solve by using quadratic formula (((6x2+3x-18=0)))
my answer is x=-2 3/2
-b+- sq root of b^2-4ac/2a
a=6
b=3
c=18
so -3+-sqrt(9-4(6)l-18/12
-3t-sqrt9441)/12
-3+-21/12 and x=-3-21/12
x=-3+21/12 and x=-3-21/12
x=18/12=3/2 and x=-2
this is how I came up with this answer is this right?

Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=12.25 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 1.5, -2. Here's your graph:

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Looks right.