SOLUTION: I would greatly appreciate help with this problem. Create a real-life situation that fits into the equation (x+3)(x-5)=0 and express the situation as the same equation.

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: I would greatly appreciate help with this problem. Create a real-life situation that fits into the equation (x+3)(x-5)=0 and express the situation as the same equation.      Log On


   

Question 204075: I would greatly appreciate help with this problem.
Create a real-life situation that fits into the equation (x+3)(x-5)=0 and express the situation as the same equation.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
I would greatly appreciate help with this problem.
Create a real-life situation that fits into the equation (x+3)(x-5)=0 and express the situation as the same equation.
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Graph the function f(x) = (x+3)(x-5) just to see what it looks like.
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graph%28400%2C300%2C-10%2C10%2C-30%2C10%2C%28x%2B3%29%28x-5%29%29
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Let "y" be "amount of money in the bank.
Or let "y" be the height of a diver above the water.
Or let "y" be altitude of an airplane above 500' in the air.
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Let "x" be time.
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The graph shows you that y decreases from -inf to x=1.
y is negative between x= -3 and x = 5;
y increases from x=1 to inf.
y is positive after x = 5
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Use that information to describe a realistic scenario modeled
by y = (x+3)(x-5)
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Cheers,
Stan H.