SOLUTION: I need help about this one as well!
If a, b, and c are three consecutive integers, find the integers if {{{c^3-a^3=866}}} in {{{a^2+c^2-2b^2=2}}}
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Quadratic Equations and Parabolas
-> SOLUTION: I need help about this one as well!
If a, b, and c are three consecutive integers, find the integers if {{{c^3-a^3=866}}} in {{{a^2+c^2-2b^2=2}}}
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Question 202023: I need help about this one as well!
If a, b, and c are three consecutive integers, find the integers if in Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! 13^3 - 11^3 = 866
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(a-11)*(a+13) = 0
a = 11
a = -13
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a^2+c^2-2b^2=2
11^2 + 13^2 - 2*12^2 is not 2, it's -8.
