SOLUTION: Dear tutor,Could you help me to solving this equation please?I do not have any idea to solve it! {{{x^4-13x^2+36=0}}}

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(x^2-9)(x^2-4)=0
(x+3)(x-3)(x+2)(x-2)=0
x+3=0
x=-3 ans.
x-3=0
x=3 ans.
x+2=0
x=-2 ans.
x-2=0
x=2 ans.

You can put this solution on YOUR website!
Start with the given equation.


Let . So


Replace with . Replace with "z"


Notice that the quadratic is in the form of where , , and


Let's use the quadratic formula to solve for "z":


Start with the quadratic formula


Plug in , , and


Negate to get .


Square to get .


Multiply to get


Subtract from to get


Multiply and to get .


Take the square root of to get .


or Break up the expression.


or Combine like terms.


or Simplify.


So the solutions in terms of "z" are or


Now recall that we let


So when , or


In other words, when , or


So the first two solutions in terms of "x" are: or


Likewise, when , or


So when , or


So the next two solutions in terms of "x" are: or


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Answer:


So the four solutions are:


, , or