SOLUTION: Hi, Could you help me to find a way to this problem?!Tanks=) One number is 6 less than a secound number.The product of the numbers is 48 more than the square of the smaller number

Algebra ->  Algebra  -> Quadratic Equations and Parabolas -> SOLUTION: Hi, Could you help me to find a way to this problem?!Tanks=) One number is 6 less than a secound number.The product of the numbers is 48 more than the square of the smaller number      Log On

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Question 201636: Hi, Could you help me to find a way to this problem?!Tanks=)
One number is 6 less than a secound number.The product of the numbers is 48 more than the square of the smaller number.Find the two numbers.
I tryed to solve with this way but i couldnt finish it:




Answer by RAY100(1608) About Me  (Show Source):
You can put this solution on YOUR website!
(1) x =y-6,,,,,,x = smaller, y = larger
.
(2) xy = 48 + x^2,,,,,product means multiply
.
subst (1) in (2)
.
y(y-6) = 48 + (y-6)^2
.
y^2 -6y = 48 + y^2 -12y +36
.
6y = 84
.
y = 14
.
.
x=y-6 = 14-6 = 8
.
check in (2),,14 * 8 = 48 + 64 = 112,,,,ok