SOLUTION: 3x2-6x=0 The 2 is suppose to be above the x...sorry..please help me

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Question 200142: 3x2-6x=0 The 2 is suppose to be above the x...sorry..please help me
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
3x%5E2-6x=0 Start with the given equation.


3x%28x-2%29=0 Factor out the GCF 3x


3x=0 or x-2=0 Set each factor equal to zero


x=0 or x=2 Solve for x in each equation


So the solutions are x=0 or x=2


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Here's another way to solve the equation:




3x%5E2-6x=0 Start with the given equation.



Notice that the quadratic 3x%5E2-6x is in the form of Ax%5E2%2BBx%2BC where A=3, B=-6, and C=0


Let's use the quadratic formula to solve for "x":


x+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29 Start with the quadratic formula


x+=+%28-%28-6%29+%2B-+sqrt%28+%28-6%29%5E2-4%283%29%280%29+%29%29%2F%282%283%29%29 Plug in A=3, B=-6, and C=0


x+=+%286+%2B-+sqrt%28+%28-6%29%5E2-4%283%29%280%29+%29%29%2F%282%283%29%29 Negate -6 to get 6.


x+=+%286+%2B-+sqrt%28+36-4%283%29%280%29+%29%29%2F%282%283%29%29 Square -6 to get 36.


x+=+%286+%2B-+sqrt%28+36-0+%29%29%2F%282%283%29%29 Multiply 4%283%29%280%29 to get 0


x+=+%286+%2B-+sqrt%28+36+%29%29%2F%282%283%29%29 Subtract 0 from 36 to get 36


x+=+%286+%2B-+sqrt%28+36+%29%29%2F%286%29 Multiply 2 and 3 to get 6.


x+=+%286+%2B-+6%29%2F%286%29 Take the square root of 36 to get 6.


x+=+%286+%2B+6%29%2F%286%29 or x+=+%286+-+6%29%2F%286%29 Break up the expression.


x+=+%2812%29%2F%286%29 or x+=++%280%29%2F%286%29 Combine like terms.


x+=+2 or x+=+0 Simplify.


So the solutions are x+=+2 or x+=+0 (note: the order of the solutions does NOT matter)


So either way, we get the same answer.