SOLUTION: {{{(z^(-8)x^8)/(x^(-8)z^0y^11)}}}

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: {{{(z^(-8)x^8)/(x^(-8)z^0y^11)}}}      Log On


   



Question 199801: %28z%5E%28-8%29x%5E8%29%2F%28x%5E%28-8%29z%5E0y%5E11%29
Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
%28z%5E%28-8%29x%5E8%29%2F%28x%5E%28-8%29z%5E0y%5E11%29

First of all, any number to the 0 power
is just one so replace the z%5E0 by 1.

%28z%5E%28-8%29x%5E8%29%2F%28x%5E%28-8%291y%5E11%29

which amounts to just erasing it:

%28z%5E%28-8%29x%5E8%29%2F%28x%5E%28-8%29y%5E11%29

Next we get rid of all negative exponents by this
pair of rules:

If any factor of the numerator has a negative exponent,
then move it from the numerator to the denominator and
change the sign of the exponent to positive:

If any factor of the denominator has a negative exponent,
then move it from the denominator to the numerator and
change the sign of the exponent to positive:

%28z%5E%28-8%29x%5E8%29%2F%28x%5E%28-8%29y%5E11%29

We move the z%5E%28-8%29 from the numerator to the 
denominator and write it with a positive exponent
z%5E8 in the denominator:

%28x%5E8%29%2F%28z%5E8x%5E%28-8%29y%5E11%29

Next we move the x%5E%28-8%29 from the denominator to the 
numerator and write it with a positive exponent
x%5E8 in the numerator:

%28x%5E8x%5E8%29%2F%28z%5E8y%5E11%29

Finally we add the exponents of x in the numerator
and we end up with:

x%5E16%2F%28z%5E8y%5E11%29

Edwin