SOLUTION: Please help me solve this problem. A parabolic arch has a span of 120 feet and a maximum height of 25 feet. Choose a suitable rectangular coordinate system and find the equat

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Please help me solve this problem. A parabolic arch has a span of 120 feet and a maximum height of 25 feet. Choose a suitable rectangular coordinate system and find the equat      Log On


   



Question 199175: Please help me solve this problem.
A parabolic arch has a span of 120 feet and a maximum height of 25 feet. Choose a suitable rectangular coordinate system and find the equation of the parabola. Then calculate the height of the arch 10, 20 and 40 feet from the center. Provide a sketch representing the situation and be sure it is clearly labled with coordinates.

Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
A parabolic arch has a span of 120 feet and a maximum height of 25 feet. Choose a suitable rectangular coordinate system and find the equation of the parabola. Then calculate the height of the arch 10, 20 and 40 feet from the center. Provide a sketch representing the situation and be sure it is clearly labled with coordinates.

The equation of the parabola with vertex (h,k) is
y=a%28x-h%29%5E2%2Bk
So the equation of the parabola with vertex (60,25) is
y=a%28x-60%29%5E2%2B25
Since it goes through (0,0) we substitute that in:
0=a%280-60%29%5E2%2B25
0=a%28-60%29%5E2%2B25
0=a%283600%29%2B25
0=3600a%2B25
-3600a=25
a=25%2F%28-3600%29
a=-1%2F144
So the equation of the parabola is
y=%28-1%2F144%29%28x-60%29%5E2%2B25
To find the height 10 feet from the center,
since the center is at 60, 10 feet from the
center is where x=50 and where x=70
we can either substitute x=50 or x=70
Substituting 50,
y=%28-1%2F144%29%2850-60%29%5E2%2B25
y=%28-1%2F144%29%28-10%29%5E2%2B25
y=%28-1%2F144%29%28100%29%2B25
y=24.3056 feet, approximately

To find the height 20 feet from the center,
since the center is at 60, 20 feet from the
center is where x=40 and where x=80
we can either substitute x=40 or x=80
Substituting 40,
y=%28-1%2F144%29%2840-60%29%5E2%2B25
y=%28-1%2F144%29%28-20%29%5E2%2B25
y=%28-1%2F144%29%28400%29%2B25
y=22.2222 feet, approximately

To find the height 40 feet from the center,
since the center is at 60, 40 feet from the
center is where x=20 and where x=100
we can either substitute x=20 or x=100
y=%28-1%2F144%29%2820-60%29%5E2%2B25
y=%28-1%2F144%29%28-40%29%5E2%2B25
y=%28-1%2F144%29%281600%29%2B25
y=13.6111feet, approximately


Edwin