SOLUTION: Solving Problems with Quadratic Equations 20 The length of a rectangular field is 2 m greater than three time sits width. The area of the field is 1496 m^2. What are the dimension

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Solving Problems with Quadratic Equations 20 The length of a rectangular field is 2 m greater than three time sits width. The area of the field is 1496 m^2. What are the dimension      Log On


   

Question 198594: Solving Problems with Quadratic Equations
20 The length of a rectangular field is 2 m greater than three time sits width. The area of the field is 1496 m^2. What are the dimensions of the field?
Thanks!!!!
Answer by arallie(162) About Me  (Show Source):
You can put this solution on YOUR website!
The length of a rectangular field is 2 m greater than three time sits width. The area of the field is 1496 m^2
Here we go
l=3w%2B2
1496=lw
1496=%283w%2B2%29w
1496=3w%5E2%2B2w
Quad Form
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+ where a=3, b=2, c=-1496
Real solutions:
Root 1: -22.6666666666667
Root 2: 22
A negative answer is not usable, therefore 22m is the width
l=3%2822%29%2B2
l=66%2B2
l=68
1496=%2822%29%2868%29
1496=1496
Check
Anymore questions feel free to ask me.
Anthony Allie
arallie@gmail.com
http://arallie.webs.com/tutoring.htm