Question 197841: Quadratic Equations
7. A basketball is tossed from the top of a 3-m wall. The path of the basketball is defined by the relation y=-x^2+2x+3, where x represents the horizontal distance travelled, in metres, and y represents the height, in metres, above the ground. How far has the basketball travelled horizontally when it lands on the ground?
Thank you very much!!!
Found 2 solutions by stanbon, solver91311:
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! A basketball is tossed from the top of a 3-m wall. The path of the basketball is defined by the relation y=-x^2+2x+3, where x represents the horizontal distance traveled, in metres, and y represents the height, in metres, above the ground. How far has the basketball traveled horizontally when it lands on the ground?
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The height of the ball is zero when it hits the ground.
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Solve -x^2 + 2x + 3 = 0
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(-x + 3)(x+1) = 0
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Positive solution:
x = 3 meters (horizontal travel distance)
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Cheers,
Stan H.
Answer by solver91311(24713)  (Show Source):
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