SOLUTION: Find b^2 - 4ac and the number of real solutions to equation -2x^(2)+5x-6=0

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Question 197330: Find b^2 - 4ac and the number of real solutions to
equation
-2x^(2)+5x-6=0
Answer by jim_thompson5910(28715) About Me  (Show Source):
You can put this solution on YOUR website!

From -2x%5E2%2B5x-6 we can see that a=-2, b=5, and c=-6


D=b%5E2-4ac Start with the discriminant formula.


D=%285%29%5E2-4%28-2%29%28-6%29 Plug in a=-2, b=5, and c=-6


D=25-4%28-2%29%28-6%29 Square 5 to get 25


D=25-48 Multiply 4%28-2%29%28-6%29 to get %28-8%29%28-6%29=48


D=-23 Subtract 48 from 25 to get -23


Since the discriminant is less than zero, this means that there are two complex solutions.


In other words, there are no real solutions.