SOLUTION: find the equation of the axis of symmetry and the coordinates of the vertex of the graph of each function. {{{y=x^2+12x-9}}} Axis of symmetry is given by {{{x=-b/2a}}} for a f

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: find the equation of the axis of symmetry and the coordinates of the vertex of the graph of each function. {{{y=x^2+12x-9}}} Axis of symmetry is given by {{{x=-b/2a}}} for a f      Log On


   

Question 196953: find the equation of the axis of symmetry and the coordinates of the vertex of the graph of each function.
y=x%5E2%2B12x-9
Axis of symmetry is given by x=-b%2F2a
for a function, f%28x%29=ax%5E2%2Bbx%2Bc
So x=-12%2F%282%2A1%29+
x=-6 is the axis of symmetry.
x coordinate of vertex is -b%2F2a
y coordinate of vertex is f%28-b%2F2a%29+=+-6%5E2%2B%2812%2A-6%29-9+=-45
So vertex = (-6,-45)
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