SOLUTION: solve 2x^2=9x. round to the nearest tenth.

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Question 195440: solve 2x^2=9x. round to the nearest tenth.
Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
2x%5E2=9x divide both sides by x (assumes x is not = 0)
2x+=+9 divide both sides by 2
x+=+9%2F2
x+=+4.5
Verify by subbing back into the original equation
Does 2*(4.5)^2 = 9*4.5