SOLUTION: Name the vertex and axis of symmetry for each quadratic function. Tell wherther the parabola opens up, down, left, or right. H(x)=-(x-6)^2+1

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Name the vertex and axis of symmetry for each quadratic function. Tell wherther the parabola opens up, down, left, or right. H(x)=-(x-6)^2+1      Log On


   

Question 194512: Name the vertex and axis of symmetry for each quadratic function. Tell wherther the parabola opens up, down, left, or right.
H(x)=-(x-6)^2+1
Answer by RAY100(1637) About Me  (Show Source):
You can put this solution on YOUR website!
Let H(x) = y
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y = (x-6)^2 +1
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(y-1) = (x-6)^2,,,,,from this we can read, vertex at (6,1),
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positive leading coefficient means it is pointing up
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Axis of symmetry is x=6
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another form might be,,, y=x^2 -12x +36 +1 = x^2 -12x +37
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vertex of x is -b/2a = -(-12)/2(1) = +6,,, subst in to get y= 1,,,,( 6,1)
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check by plotting a few points, (6,1),,,,(5,2),,,,(7,2)