SOLUTION: To solve percent mixture problems:
How many quarts of water must be added to 5 qt. of an 80% antifreeze solution to make a 50% antifreeze solution?
my try:
Water x
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-> SOLUTION: To solve percent mixture problems:
How many quarts of water must be added to 5 qt. of an 80% antifreeze solution to make a 50% antifreeze solution?
my try:
Water x
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Question 192446This question is from textbook Intermediate Algebra
: To solve percent mixture problems:
How many quarts of water must be added to 5 qt. of an 80% antifreeze solution to make a 50% antifreeze solution?
my try:
Water x 1.00 x
80% 75 .80 75(.80)
50% 75+x .50 .50(75+x)
x+75(80) =50(75+x)
x+6000=3750 + 50x
-49x = -2250
x = -45.91
????
Wrong? This question is from textbook Intermediate Algebra
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