SOLUTION: "x" varies direcly as the square of "s" and inversely as "t". How does "x" change when "s" is doubled? When both "s" and "t" are doubled? I figured "x" = "k" "s"

Algebra ->  Algebra  -> Quadratic Equations and Parabolas -> SOLUTION: "x" varies direcly as the square of "s" and inversely as "t". How does "x" change when "s" is doubled? When both "s" and "t" are doubled? I figured "x" = "k" "s"       Log On

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Question 19232: "x" varies direcly as the square of "s" and inversely as "t". How does "x" change when "s" is doubled? When both "s" and "t" are doubled?
I figured "x" = "k" "s" squared divided by "t" (using "k" as a non zero constant but I'm stuck.
Answer by Earlsdon(6103) About Me  (Show Source):
You can put this solution on YOUR website!
Try this:
x+=+ks%5E2%2Ft Multipy s by 2.
x+=+k%282s%29%5E2%2Ft = 4%28ks%5E2%29%2Ft+=+4x So, x is quadrupled when s is doubled.
x+=+ks%5E2%2Ft Multiply s and t by 2.
x+=+k%282s%29%5E2%2F2t
x+=+4ks%5E2%2F2t = 2ks%5E2%2Ft+=+2x So, x is doubled when both s and t are doubled.