SOLUTION: Solve 4x^3-36x=0 4x(x^2-9) where do I go from here?

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Question 187600This question is from textbook saxon algebra 2
: Solve 4x^3-36x=0
4x(x^2-9)
where do I go from here? This question is from textbook saxon algebra 2

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Solve 4x^3-36x=0
4x(x^2-9)
= 4x(x-3)(x+3)
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A difference of 2 squares is always like that.
x^2 - a^2 = (x-a)*(x+a)