SOLUTION: The path of a falling object is given by the function s=-16t^+v*t+s If a rock is thrown upward with an initial velocity of 64 feet per second from the top of a 25ft building, wr

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: The path of a falling object is given by the function s=-16t^+v*t+s If a rock is thrown upward with an initial velocity of 64 feet per second from the top of a 25ft building, wr      Log On


   

Question 183304This question is from textbook
: The path of a falling object is given by the function s=-16t^+v*t+s
If a rock is thrown upward with an initial velocity of 64 feet per second from the top of a 25ft building, write the height equation using this information
a. how highis the rock after 1 second This question is from textbook

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
s=-16t%5E2%2Bv%2At%2Bs%5B0%5D Start with the given equation.


s=-16t%5E2%2B64t%2B25 Plug in v=64 (the initial velocity) and s%5B0%5D=25 (the initial height)


So the equation that models this problem is s=-16t%5E2%2B64t%2B25


a)

s=-16t%5E2%2B64t%2B25 Start with the given equation.


s=-16%281%29%5E2%2B64%281%29%2B25 Plug in t=1.


s=-16%281%29%2B64%281%29%2B25 Square 1 to get 1.


s=-16%2B64%281%29%2B25 Multiply -16 and 1 to get -16.


s=-16%2B64%2B25 Multiply 64 and 1 to get 64.


s=73 Combine like terms.


So after 1 second, the rock is 73 ft in the air.