SOLUTION: The directions say to solve using the quadratic formula. Round to the nearest tenth if necessary. The problem is written as follows: {{{x^2-25=0}}}

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: The directions say to solve using the quadratic formula. Round to the nearest tenth if necessary. The problem is written as follows: {{{x^2-25=0}}}      Log On


   

Question 180567This question is from textbook Algebra I
: The directions say to solve using the quadratic formula. Round to the nearest tenth if necessary.
The problem is written as follows:
x%5E2-25=0 This question is from textbook Algebra I

Found 2 solutions by nerdybill, mgmoeab:
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
When solving a quadratic, always try to factor first -- only if you can't should you resort to the quadratic formula.
.
x%5E2-25=0
Factoring:
%28x-5%29%28x%2B5%29=0
.
x = {-5, 5}

Answer by mgmoeab(37) About Me  (Show Source):
You can put this solution on YOUR website!
+x%5E2+-+25+=+0+
IN THIS CASE
a= 1
b= 0
c= -25
---
USING
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
WE HAVE
x+=+%28+%2B-+sqrt%28+-4%2A%281%29%2A%28-25%29+%29%29%2F%282%2A%281%29%29+
x+=+%28+%2B-+sqrt%28+100%29+%29%2F%282%29+
x+=+%28+%2B-+%2810%29++%29%2F%282%29+
Whixh gives you the values of
x = -5 and x = 5
There's is no need to round in this case