SOLUTION: y=1/1800(x-600)(x+600) x and y are measured in meters 1)how wide is the crater if y=0 and what is the depth of the crater?

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Question 179785: y=1/1800(x-600)(x+600) x and y are measured in meters
1)how wide is the crater if y=0 and what is the depth of the crater?

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
:
y =1%2F1800(x-600)(x+600) x & y are measured in meters
:
1)how wide is the crater if y=0 and what is the depth of the crater?
:
Multiply equation by 1800
(x+600)(x-600) = 0
x = +600, x = -600
Difference between intercepts = 1200 meters
:
Find the min using the original equation
:
y =1%2F1800(x-600)(x+600)
:
y = %28x%5E2+-+360000%29%2F1800
:
y = %28x%5E2%2F1800%29 - %28360000%2F1800%29
:
y = %28x%5E2%2F1800%29+-+200
:
difference of squares so axis of symmetry is 0
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in the above equation, y = -200, when x = 0
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depth of the crater = 200 meters:
Like this
+graph%28+300%2C+200%2C+-700%2C+700%2C+-250%2C+100%2C+x%5E2%2F1800+-200%29
:
Crater is 1200 m wide and 200 m deep