SOLUTION: Find the transformational form of the quadratic function having vertex (-3,4) and x-intercept (-6,0).

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Find the transformational form of the quadratic function having vertex (-3,4) and x-intercept (-6,0).      Log On


   

Question 177930: Find the transformational form of the quadratic function having vertex (-3,4) and x-intercept (-6,0).
Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!
%281%2Fk%29%28y-k%29=%28x-h%29%5E2...vertex is(-3,4)
:
%281%2Fk%29%28y-4%29=%28x%2B3%29%5E2 and we have another point(-6,0)
:
%281%2Fk%29%280-4%29=%28-6%2B3%29%5E2
:
%281%2Fk%29%28-4%29=9
:
%281%2Fk%29=-9%2F4
:
%28-9%2F4%29%28y-4%29=%28x%2B3%29%5E2