SOLUTION: Solve 2x^2-6x-3=0 Which one is the answer? I can work it all the way to were x= +6 � &#8730;60/4...I get stuck after that part. A) -3+&#8730;15/2 and -3-&#8730;15/2 B) 3+

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Question 176790: Solve 2x^2-6x-3=0 Which one is the answer? I can work it all the way to were x= +6 � √60/4...I get stuck after that part.
A) -3+√15/2 and -3-√15/2
B) 3+2√15/2 and 3-2√15/2
C) There are no real solutions
D) 3+√15/2 and 3-√15/2

Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website!
Solve 2x^2-6x-3=0 Which one is the answer? I can work it all the way to were x= +6 � √60/4...I get stuck after that part.
A) -3+√15/2 and -3-√15/2
B) 3+2√15/2 and 3-2√15/2
C) There are no real solutions
D) 3+√15/2 and 3-√15/2
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Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=60 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 3.43649167310371, -0.436491673103709. Here's your graph:

6+sqrt(60))/4 = (3+sqrt(15))/2
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sqrt(60) = sqrt(4*15) = sqrt(4)*sqrt(15) = 2sqrt(15)
You had it done, except for that.

SOLUTION: Solve 2x^2-6x-3=0 Which one is the answer? I can work it all the way to were x= +6 � &#8730;60/4...I get stuck after that part. A) -3+&#8730;15/2 and -3-&#8730;15/2 B) 3+

SOLUTION: Solve 2x^2-6x-3=0 Which one is the answer? I can work it all the way to were x= +6 � √60/4...I get stuck after that part. A) -3+√15/2 and -3-√15/2 B) 3+