SOLUTION: 3x^4 -2x^3 + 5x^2 + x + 1; x^2+2x Please explain step by step I would really appreciate any help

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: 3x^4 -2x^3 + 5x^2 + x + 1; x^2+2x Please explain step by step I would really appreciate any help      Log On


   



Question 172908: 3x^4 -2x^3 + 5x^2 + x + 1; x^2+2x
Please explain step by step
I would really appreciate any help

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
I assume that you want to do long division right?


%283x%5E4-2x%5E3%2B5x%5E2%2Bx%2B1%29%2F%28x%5E2%2B2x%29 Start with the given expression


Rewrite the expression like this:

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Now the question is: How many times does x%5E2 go into 3x%5E4?


It goes in 3x%5E2 times. So place 3x%5E2 over the term 5x%5E2.


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Now multiply 3x%5E2 by x%5E2%2B2x to get 3x%5E4%2B6x%5E3


Reverse the signs of 3x%5E4%2B6x%5E3 to get -3x%5E4-6x%5E3 (place this underneath the dividend)





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Now Add to get:

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Now the question is now: How many times does x%5E2 go into -8x%5E3?


It goes in -8x times. Place this term over x in the dividend.


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Now multiply -8x by x%5E2%2B2x to get -8x%5E3-16x%5E2


Reverse the signs of -8x%5E3-16x%5E2 to get 8x%5E3%2B16x%5E2 (place this underneath the last polynomial)


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Now add to get:

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Now how many times does x%5E2 go into 21x%5E2?


It goes in 21 times. Place this over the term 1 in the dividend.


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Now multiply 21 by x%5E2%2B2x to get 21x%5E2%2B42x


Reverse the signs of 21x%5E2%2B42x to get -21x%5E2-42x


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Now add to get:

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Since x%5E2 does NOT go into -41x%2B1. This means that the long division process stops.


So the quotient is 3x%5E2-8x%2B21 and the remainder is -41x%2B1



This means that