SOLUTION: Is there a shortcut in determining where the y-coordinate of the vertex?

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Question 170: Is there a shortcut in determining where the y-coordinate of the vertex?
Answer by KMST(5483) About Me  (Show Source):
You can put this solution on YOUR website!
If you are faced with a quadratic function such as y=x%5E2-x-6 ,
you should know that it will have a curved graph
that will look like the graph of y=x%5E2 , graph%28100%2C125%2C-2%2C2%2C-1%2C4%2Cx%5E2%29 ,
maybe stretched in one or another direction,
and/or shifted (moved, we like to say "traslated"),
and/or or flipped.

THE SHORTCUTS:
IF YOU GET LUCKY, the polynomial factors easily, as in y=x%5E2-x-6=%28x-3%29%28x%2B2%29 ,
and the roots of the polynomial are obvious,
like x=3 and x=-2 for y=x%5E2-x-6 ,
Then you realize, that as quadratics graph as symmetrical curves (parabolas),
the x-coordinate of the vertex, x%5BV%5D is at equal distance to both roots,
and can be calculated as their average, as in x%5BV%5D=3-2%29%2F2=0.5=1%2F2 .

YOU CAN MEMORIZE A FORMULA, such as x%5BV%5D=-b%2F2a for y=ax%5E2%2Bbx%2Bc
or remember it as part of

that tells you that -b%2F2a would be the average of the 2 roots of the polynomial if the polynomial had real roots.
(This shortcut works even if there are no real roots).