SOLUTION: I have no clue how to do this. I am working on quadratic functions and their graphs in intermediate algebra. This is one question with three parts: A. Write the function y=3(x

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: I have no clue how to do this. I am working on quadratic functions and their graphs in intermediate algebra. This is one question with three parts: A. Write the function y=3(x      Log On


   

Question 1671: I have no clue how to do this. I am working on quadratic functions and their graphs in intermediate algebra. This is one question with three parts:
A. Write the function y=3(x-2)^2+6 in the form of Y=ax^2 +bx+c, and find the
vertex of the parabola using the formula x=-b/2a
B. Repeat part (a) with the functions y=-4((x-5)^2-9 and y=3(x+2)^2-6.
C. What is the vertex for a parabola that is written in the form y=a(x-h)^2+k?
Explain your answer.
Found 2 solutions by smartdude17, longjonsilver:
Answer by smartdude17(30) About Me  (Show Source):
You can put this solution on YOUR website!
WOW, I've already finished this topic and I'm in seventh grade(lol). Well to find the vertex of a parabola, you use -b/2a. Your equation is this and I'll try to help you solve it from the way you have written it.
y=3(x-2)^2+6
Now you would clear the parenthesis by:
y=3(x^2-4)+6 this turns into this:
y=3x^2-12+6
Now you need to simplify it:
y=3x^2-6
Now you can do the QF (quadratic formula)
x=%280%2B-sqrt%280%2B72%29%29%2F%286%29 Substitution
x=%28%2B-4sqrt%2818%29%29%2F%286%29
And this is your scantron answer. Or you could do method #2.
x=%280%2B-8+8%2F17%29%29%2F%286%29
So this is x=%28%2B-8+8%2F17%29%29%2F%286%29
And now you M.A.D. it by multiplying 17 and 8 then adding 8 which equals 144/17 and then you multiply it with 1/6 which equals 24/17 and -24/17

Answer by longjonsilver(2297) About Me  (Show Source):
You can put this solution on YOUR website!
to amend the other solution...
y=3%28x-2%29%5E2%2B6 is y=3%28x%5E2+-+4x+%2B+4%29+%2B+6, so it is y=%283x%5E2-12x%2B12%29%2B6 and hence y=3x%5E2+-+12x+%2B+18. Then use your formula. It should be a nice number this time.
Jon