SOLUTION: Solve: x = 2+ sqrt2-x I have: (x-2)^2 = (sqrt2 - x)^2 x^2 - 4x + 4 = 2 - 1x x^2 - 3x + 2 = 0 (x-1) (x -2)answer Please let me know what you think? correct or

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Solve: x = 2+ sqrt2-x I have: (x-2)^2 = (sqrt2 - x)^2 x^2 - 4x + 4 = 2 - 1x x^2 - 3x + 2 = 0 (x-1) (x -2)answer Please let me know what you think? correct or       Log On


   

Question 162905This question is from textbook
:
Solve: x = 2+ sqrt2-x

I have:
(x-2)^2 = (sqrt2 - x)^2
x^2 - 4x + 4 = 2 - 1x
x^2 - 3x + 2 = 0
(x-1) (x -2)answer
Please let me know what you think? correct or no. This question is from textbook

Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
When you got here:
x^2 - 3x + 2 = 0
You factored to get:
(x-1)(x-2) = 0
.
Two solutions are possible:
solution 1:
(x-1) = 0
x-1 = 0
x = 1
solution 2:
(x-2) = 0
x-2 = 0
x = 2
.
Conclusion:
x = {1,2}