SOLUTION: 8x^6-7x^3y^3-y^6

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Question 156973: 8x^6-7x^3y^3-y^6
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Do you want to factor this?


Looking at 8x%5E6-7x%5E3y%5E3-y%5E6 we can see that the first term is 8x%5E6 and the last term is -y%5E6 where the coefficients are 8 and -1 respectively.

Now multiply the first coefficient 8 and the last coefficient -1 to get -8. Now what two numbers multiply to -8 and add to the middle coefficient -7? Let's list all of the factors of -8:



Factors of -8:
1,2,4,8

-1,-2,-4,-8 ...List the negative factors as well. This will allow us to find all possible combinations

These factors pair up and multiply to -8
(1)*(-8)
(2)*(-4)
(-1)*(8)
(-2)*(4)

note: remember, the product of a negative and a positive number is a negative number


Now which of these pairs add to -7? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to -7

First NumberSecond NumberSum
1-81+(-8)=-7
2-42+(-4)=-2
-18-1+8=7
-24-2+4=2



From this list we can see that 1 and -8 add up to -7 and multiply to -8


Now looking at the expression 8x%5E6-7x%5E3y%5E3-y%5E6, replace -7x%5E3y%5E3 with x%5E3y%5E3%2B-8x%5E3y%5E3 (notice x%5E3y%5E3-8x%5E3y%5E3 adds up to -7x%5E3y%5E3. So it is equivalent to -7x%5E3y%5E3)

8x%5E6%2Bhighlight%28x%5E3y%5E3-8x%5E3y%5E3%29-y%5E6


Now let's factor 8x%5E6%2Bx%5E3y%5E3-8x%5E3y%5E3-y%5E6 by grouping:


%288x%5E6%2Bx%5E3y%5E3%29%2B%28-8x%5E3y%5E3-y%5E6%29 Group like terms


x%5E3%288x%5E3%2By%5E3%29-y%5E3%288x%5E3%2By%5E3%29 Factor out the GCF of x%5E3 out of the first group. Factor out the GCF of -y%5E3 out of the second group


%28x%5E3-y%5E3%29%288x%5E3%2By%5E3%29 Since we have a common term of 8x%5E3%2By%5E3, we can combine like terms


So 8x%5E6-7x%5E3y%5E3-y%5E6 factors to %28x%5E3-y%5E3%29%288x%5E3%2By%5E3%29


%28x-y%29%28x%5E2%2Bxy%2By%5E2%29%282x%2By%29%284x%5E2-2xy%2By%5E2%29 Now factor x%5E3-y%5E3 to get %28x-y%29%28x%5E2%2Bxy%2By%5E2%29 (use the difference of cubes formula) and factor 8x%5E3%2By%5E3 to get %282x%2By%29%284x%5E2-2xy%2By%5E2%29 (use the sum of cubes formula)


%28x-y%29%282x%2By%29%28x%5E2%2Bxy%2By%5E2%29%284x%5E2-2xy%2By%5E2%29 Rearrange the factors


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Answer:
So 8x%5E6-7x%5E3y%5E3-y%5E6 completely factors to %28x-y%29%282x%2By%29%28x%5E2%2Bxy%2By%5E2%29%284x%5E2-2xy%2By%5E2%29