SOLUTION: We are suppose to use the method that came from India to solve our problems, but I'm lost. x^2-2x-13=0 x^2-2x-13+13=0 x^2-2x=13 4x^2-8x=52 4x^2-8x+4=52+4 4x^2-8x+4=56 the

Algebra ->  Algebra  -> Quadratic Equations and Parabolas -> SOLUTION: We are suppose to use the method that came from India to solve our problems, but I'm lost. x^2-2x-13=0 x^2-2x-13+13=0 x^2-2x=13 4x^2-8x=52 4x^2-8x+4=52+4 4x^2-8x+4=56 the       Log On

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Question 154135: We are suppose to use the method that came from India to solve our problems, but I'm lost.
x^2-2x-13=0
x^2-2x-13+13=0
x^2-2x=13
4x^2-8x=52
4x^2-8x+4=52+4
4x^2-8x+4=56
the next step and there after I'm lost, could you please help me out
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Solve by "the method that came from India":
x%5E2-2x-13+=+0
Now I've never been to India, but the method to which you are refering is also known as "completing the square" and here's how you do that:
x%5E2-2x-13+=+0 First, add 13 to both sides of the equation.
x%5E2-2x+=+13 Now "complete the square" in x by adding the square of half the x-coefficient to both sides of the equation. This would be: %28-2%2F2%29%5E2+=+1
x%5E2-2x%2B1+=+13%2B1 Simplify.
x%5E2-2x%2B1+=+14 Now factor the left side of the equation.
%28x-1%29%28x-1%29+=+14 Rewrite the left sides as:
%28x-1%29%5E2+=+14 Now take the square root of both sides.
x-1+=+0%2B-sqrt%2814%29 Finally, add 1 to both sides.
highlight%28x+=+1%2B-sqrt%2814%29%29