Questions on Algebra: Quadratic Equation answered by real tutors!

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Question 150932: How do you factor by grouping, 48x^2y + 20xz +12xy + 5z, whats the answer?: How do you factor by grouping, 48x^2y + 20xz +12xy + 5z, whats the answer?
Answer by jim_thompson5910(8735) About Me  (Show Source):
You can put this solution on YOUR website!
48x^2y+20xz+12xy+5z Start with the given expression

(48x^2y+20xz)+(12xy+5z) Group the terms into two groups


4x(12xy+5z)+1(12xy+5z) Factor out the GCF 4x out of the first group. Factor out the GCF 1 out of the second group


(4x+1)(12xy+5z) Since we have the common term 12xy+5z, we can combine like terms

So 48x^2y+20xz+12xy+5z factors to (4x+1)(12xy+5z)
Question 150932: How do you factor by grouping, 48x^2y + 20xz +12xy + 5z, whats the answer?: How do you factor by grouping, 48x^2y + 20xz +12xy + 5z, whats the answer?
Answer by ankor@dixie-net.com(4182) About Me  (Show Source):
You can put this solution on YOUR website!
How do you factor by grouping, 48x^2y + 20xz +12xy + 5z,
;
Rearrange like this:
48x^2y + 12xy + 20xz + 5z
;
It's now apparent that we can factor 12xy and 5z like this;
12xy(4x + 1) + 5z(4x + 1)
:
Factor out (4x+1) and we have:
(4x + 1)(12xy + 5z)