Questions on Algebra: Quadratic Equation answered by real tutors!

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Question 150929: sketch the graph of f(x) + (x-3)2 + 1: sketch the graph of f(x) + (x-3)2 + 1
Answer by jim_thompson5910(8743) About Me  (Show Source):
You can put this solution on YOUR website!

Table of Contents:

Table
Graph

In order to graph y=(x-3)^2 + 1, we need to plot a few points.


Let's find the y value when x=0 note: you can start at any x value.


y=(x-3)^2 + 1 Start with the given equation.


y=(0-3)^2 + 1 Plug in x=0.


y=10 Simplify.


So when x=0, y=10. So we have the point (0,10).


----------------------------


Let's find the y value when x=1


y=(x-3)^2 + 1 Start with the given equation.


y=(1-3)^2 + 1 Plug in x=1.


y=5 Simplify.


So when x=1, y=5. So we have the point (1,5).


----------------------------


Let's find the y value when x=2


y=(x-3)^2 + 1 Start with the given equation.


y=(2-3)^2 + 1 Plug in x=2.


y=2 Simplify.


So when x=2, y=2. So we have the point (2,2).


----------------------------


Let's find the y value when x=3


y=(x-3)^2 + 1 Start with the given equation.


y=(3-3)^2 + 1 Plug in x=3.


y=1 Simplify.


So when x=3, y=1. So we have the point (3,1).


----------------------------


Let's find the y value when x=4


y=(x-3)^2 + 1 Start with the given equation.


y=(4-3)^2 + 1 Plug in x=4.


y=2 Simplify.


So when x=4, y=2. So we have the point (4,2).


----------------------------


Let's find the y value when x=5


y=(x-3)^2 + 1 Start with the given equation.


y=(5-3)^2 + 1 Plug in x=5.


y=5 Simplify.


So when x=5, y=5. So we have the point (5,5).


----------------------------


Let's find the y value when x=6


y=(x-3)^2 + 1 Start with the given equation.


y=(6-3)^2 + 1 Plug in x=6.


y=10 Simplify.


So when x=6, y=10. So we have the point (6,10).


----------------------------


Now let's make a table of the values we just found.





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Table of Values:


xy
010
15
22
31
42
55
610

Now let's plot the points:


 drawing(900, 900, -12, 12, -12, 12,<BR>
grid(1),<BR>
graph(900, 900, -12, 12, -12, 12, 0),<BR>
circle(0,10,0.08),circle(0,10,0.10),<BR>
circle(1,5,0.08),circle(1,5,0.10),<BR>
circle(2,2,0.08),circle(2,2,0.10),<BR>
circle(3,1,0.08),circle(3,1,0.10),<BR>
circle(4,2,0.08),circle(4,2,0.10),<BR>
circle(5,5,0.08),circle(5,5,0.10),<BR>
circle(6,10,0.08),circle(6,10,0.10)
<BR>

)




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Graph:


Now draw a curve through all of the points to graph y=(x-3)^2 + 1:


 drawing(900, 900, -12, 12, -12, 12,<BR>
grid(1),<BR>
graph(900, 900, -12, 12, -12, 12, (x-3)^2 + 1),<BR>
circle(0,10,0.08),circle(0,10,0.10),<BR>
circle(1,5,0.08),circle(1,5,0.10),<BR>
circle(2,2,0.08),circle(2,2,0.10),<BR>
circle(3,1,0.08),circle(3,1,0.10),<BR>
circle(4,2,0.08),circle(4,2,0.10),<BR>
circle(5,5,0.08),circle(5,5,0.10),<BR>
circle(6,10,0.08),circle(6,10,0.10)
<BR>

) Graph of y=(x-3)^2 + 1