Questions on Algebra: Quadratic Equation answered by real tutors!

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Question 150924: x^2-5x-14 4
________ . ____
8 x-7: x^2-5x-14 4
________ . ____
8 x-7
Answer by jim_thompson5910(8066) About Me  (Show Source):
You can put this solution on YOUR website!

((x^2-5x-14)/(8))((4)/(x-7)) Start with the given expression.


(((x+2)(x-7))/((2)(4)))((4)/(x-7)) Factor x^2-5x-14 to get (x+2)(x-7).


(((x+2)(x-7))/((2)(4)))((4)/(x-7)) Factor 8 to get (2)(4).


((x+2)(x-7)(4))/((2)(4)(x-7)) Combine the fractions.


((x+2)highlight((x-7))highlight(4))/((2)highlight(4)highlight((x-7))) Highlight the common terms.


((x+2)cross((x-7))cross(4))/((2)cross(4)cross((x-7))) Cancel out the common terms.


(x+2)/(2) Simplify.


So ((x^2-5x-14)/(8))((4)/(x-7)) simplifies to (x+2)/(2).


In other words, ((x^2-5x-14)/(8))((4)/(x-7))=(x+2)/(2) where x<>7
Question 150924: x^2-5x-14 4
________ . ____
8 x-7: x^2-5x-14 4
________ . ____
8 x-7
Answer by stanbon(17617) About Me  (Show Source):
You can put this solution on YOUR website!
x^2-5x-14 4
________ . ____
8 x-7
-----------------------
Factor to get:
[(x-7)(x+2)/8] * [4/(x-7)]
Cancel factors common to a numerator and a denominator:
= (x+2)/2
=================
Cheers,
Stan H.