SOLUTION: Find the value for the correlation coefficient r x 5, 1, 4, 2, 3 ----------- ----------- - y 5, 10, 12, 4, 8 Can anyone help?

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Find the value for the correlation coefficient r x 5, 1, 4, 2, 3 ----------- ----------- - y 5, 10, 12, 4, 8 Can anyone help?      Log On


   

Question 150568: Find the value for the correlation coefficient r
x 5, 1, 4, 2, 3
-------------------------
y 5, 10, 12, 4, 8

Can anyone help?
Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
 Find the value for the correlation coefficient r 

x | 5,  1,  4, 2, 3 
--------------------
y | 5, 10, 12, 4, 8 

Can anyone help?


It's a terrible formula! But if you have a TI-83 
or TI-84, you can find it easily.

First you have to turn the Diagnostics On; 
otherwise the correlation coefficient won't
be displayed with the regression line equation.

You press 2nd 0 for CATALOG
Scroll down alphabetically to Diagnostics On
Press ENTER and you'll see "Done".

Then they will stay on as long as you don't
turn the Diagnostics Off

--------------

Now press STAT 1

Put

5 1 4 2 3 in L1

and

5 10 12 4 8 in L2

Press STAT and the right arrow to highlight CALC

Press 4 for  LinReg(ax+b)

Then press ENTER

You see

LinReg
 y=ax+b
 a=-.2
 n=8.4
 rē=.0089285714
 r=-.0944911183

That value of r is the regression coefficient.
That is very small in absolute value, which
means that the points are not very close to 
falling in a straight line.

Edwin