SOLUTION: y=x^2+2x+1 I discriminant for this what I have can you tell me if this right. d=b^2-4ac, 2*2^2-4*1*1, 8-4=4

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: y=x^2+2x+1 I discriminant for this what I have can you tell me if this right. d=b^2-4ac, 2*2^2-4*1*1, 8-4=4      Log On


   

Question 150315This question is from textbook
: y=x^2+2x+1 I discriminant for this what I have can you tell me if this right.
d=b^2-4ac, 2*2^2-4*1*1, 8-4=4 This question is from textbook

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

From x%5E2%2B2x%2B1 we can see that a=1, b=2, and c=1


D=b%5E2-4ac Start with the discriminant formula


D=%282%29%5E2-4%281%29%281%29 Plug in a=1, b=2, and c=1


D=4-4%281%29%281%29 Square 2 to get 4


D=4-4 Multiply 4%281%29%281%29 to get %284%29%281%29=4


D=0 Subtract 4 from 4 to get 0


Since the discriminant is equal to zero, this means that there is one real solution