SOLUTION: Finding 3 consecutive positive integers such the product of the first and the third is 60.
Algebra
->
Quadratic Equations and Parabolas
-> SOLUTION: Finding 3 consecutive positive integers such the product of the first and the third is 60.
Log On
Quadratics: solvers
Quadratics
Practice!
Practice
Answers archive
Answers
Lessons
Lessons
Word Problems
Word
In Depth
In
Click here to see ALL problems on Quadratic Equations
Question 149425
:
Finding 3 consecutive positive integers such the product of the first and the third is 60.
Answer by
Alan3354(69443)
(
Show Source
):
You can
put this solution on YOUR website!
Finding 3 consecutive positive integers such the product of the first and the third is 60.
---------------
Those would be n and n+2.
n*(n+4) = 60
n^2 + 4n - 60 = 0
(n+10)*(n-6) = 0
n = 6
