SOLUTION: I have to sove using the quadric formula and if there are no real roots say so...Please help me ands thanks...:) Page 588 Number 20 3x^2 - 4x + 2 = 0

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Question 146572This question is from textbook Beginning Algebra
: I have to sove using the quadric formula and if there are no real roots say so...Please help me ands thanks...:)
Page 588
Number 20
3x^2 - 4x + 2 = 0
This question is from textbook Beginning Algebra

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
3x%5E2+-+4x+%2B+2+=+0
Same as the others.
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 3x%5E2%2B-4x%2B2+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%28-4%29%5E2-4%2A3%2A2=-8.

The discriminant -8 is less than zero. That means that there are no solutions among real numbers.

If you are a student of advanced school algebra and are aware about imaginary numbers, read on.


In the field of imaginary numbers, the square root of -8 is + or - sqrt%28+8%29+=+2.82842712474619.

The solution is , or
Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+3%2Ax%5E2%2B-4%2Ax%2B2+%29

This one has no real roots.