SOLUTION: Good morning everyone. I am having an issue with Axis of Symmetry and Vertex. The problem is: Y=x2-5 Please help

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Good morning everyone. I am having an issue with Axis of Symmetry and Vertex. The problem is: Y=x2-5 Please help      Log On


   

Question 143811This question is from textbook McDougal Littell Algebra 1
: Good morning everyone.
I am having an issue with Axis of Symmetry and Vertex.
The problem is: Y=x2-5
Please help This question is from textbook McDougal Littell Algebra 1

Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
the general equation for the axis of symmetry is x=-b/(2a)

in this case, since b=0 (no x term), the equation for the axis of symmetry is x=0

the axis of symmetry goes through the vertex __ so the x-coordinate is 0

substituting __ y=0^2-5 __ y=-5

vertex is at (0,-5)