SOLUTION: The length of a rectangle is two feet more than four times its width. find the width given the area is 42 feet.
what i have done:
42=4(x+2)
42=4x+8
0=4x-34
Algebra ->
Quadratic Equations and Parabolas
-> SOLUTION: The length of a rectangle is two feet more than four times its width. find the width given the area is 42 feet.
what i have done:
42=4(x+2)
42=4x+8
0=4x-34
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Question 143808: The length of a rectangle is two feet more than four times its width. find the width given the area is 42 feet.
what i have done:
42=4(x+2)
42=4x+8
0=4x-34
You can put this solution on YOUR website! width=x
length=4x+2
x(4x+2)=42
4x^2+2x-42=0
2x^2+x-21=0
solutions are 3 and -7/2
so x=3
and 4x+2=14
Answer: width is 3 feets
