SOLUTION: Solve using the quadratic formula: y^2-3y-10=0

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Question 143158: Solve using the quadratic formula:
y^2-3y-10=0
Answer by checkley77(12844) About Me  (Show Source):
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y^2-3y-10=0
y+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
y=(3+-sqrt[-3^2-4*1*-10])/2*1
y=(3+-sqrt[9+40])/2
y=(3+-sqrt49)/2
y=3+-7)/2
y=(3+7)/2
y=10/2
y=5 answer.
y=(3-7)/2
y=-4/2
y=-2 answer.