SOLUTION: Sorry the question wasnt done yet...Find the indicated outputs for
f(x)= 2x2 - 5x
(The second 2 is too the power of)(one of those little 2's above the number)
f(0)=
f(-1)=
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Quadratic Equations and Parabolas
-> SOLUTION: Sorry the question wasnt done yet...Find the indicated outputs for
f(x)= 2x2 - 5x
(The second 2 is too the power of)(one of those little 2's above the number)
f(0)=
f(-1)=
Log On
Question 141698: Sorry the question wasnt done yet...Find the indicated outputs for
f(x)= 2x2 - 5x
(The second 2 is too the power of)(one of those little 2's above the number)
f(0)=
f(-1)=
f(2)=
HELP PLEASE!!!!! Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! f(x)= 2x^2 - 5x
(The second 2 is too the power of)(one of those little 2's above the number)
f(0)= 2(0)^2 - 5*2 = 2*0-5*2 = -10
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f(-1)= 2(1)^2 - 5*1 = 2*1 - 5 = -3
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f(2)= 2(2)^2 - 5*2 = 2*4 - 10 = -2
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Cheers,
Stan H.
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