SOLUTION: I have tried this problem and I have the answer but im not getting the answer... I get another one. the problem is 25x2-20x=-3 I changed the problem to read 25x2-20x+3=0 then used

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: I have tried this problem and I have the answer but im not getting the answer... I get another one. the problem is 25x2-20x=-3 I changed the problem to read 25x2-20x+3=0 then used       Log On


   

Question 139188: I have tried this problem and I have the answer but im not getting the answer... I get another one. the problem is 25x2-20x=-3 I changed the problem to read 25x2-20x+3=0 then used the quadratic formula of X=-b+-the square root of b-4ac over 2a I came up with X=2+-1/5 the answer is supposed to be 1/5 and 3/5
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+

where a=25, b=-20, and c=3



x+=+%2820+%2B-+sqrt%28400-300%29%29%2F50+

x+=+%2820+%2B-+sqrt%28100%29%29%2F50+

x+=+%2820+%2B-+10%29%2F50+

x+=+30%2F50=3%2F5 or x=10%2F50=1%2F5

Apparently your arithmetic was faulty. Go back and compare your work to mine.

Super-Double-Plus-Extra Credit: How could you tell for certain that 1%2F5 and 3%2F5 are the actual roots of the equation? (There are 2 different methods)