SOLUTION: What three techniques can be used to solve a quadratic equation? Please could you demonstrate all three techniques using the following equation. Thanks! 12x^2 - 10x

Click here to see ALL problems on Quadratic Equations

Question 139153: What three techniques can be used to solve a quadratic equation? Please could you demonstrate all three techniques using the following equation. Thanks!
12x^2 - 10x - 42 = 0
Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website!
12x^2-10x-42=0
2(6x^2-5x-21)=0
2(2x+3)(3x-7)=0
2x+3=0
2x=-3
x=-3/2 answer.
3x-7=0
3x=7
x=7/3 answer.
-----------------------------------
12x^2-10x-42=0
(4x+6)(6x-14)=0
4x+6=0
4x=-6
x=-6/4
x=-3/2 answer.
6x-14=0
6x=14
x=14/6
x=7/3 answer.
------------------------------------
12x^2-10x-42=0
using the quadratic equation: we get:
x=(10+-sqrt[-10^2-4*12*-42])/2*12
x=(10+-sqrt[100+2016])/24
x=(10+-sqrt2116)/24
x=(10+-46)/24
x=(10+46)/24
x=56/24
x=7/3 aanswer.
x=(10-46)/24
x=-36/24
x=-3/2 answer.

SOLUTION: What three techniques can be used to solve a quadratic equation? Please could you demonstrate all three techniques using the following equation. Thanks! 12x^2 - 10x - 42 = 0