SOLUTION: Solve for x: logbasex(3x+10)=logbase7 49

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Question 138585: Solve for x: logbasex(3x+10)=logbase7 49
Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
log[x](3x+10)=log[7](49)
log[x](3x+10)=2
x^log[x](3x+10)=x^2
3x+10=x^2
x^2-3x-10=0
(x-5)(x+2)=0
x=5
.
Ed