SOLUTION: Solve by the elimination method.
0.05x+0.25y=11
0.15x+0.05=12
What is the solution of the system?
Again can someone explain how I am supposed to do this? I do not seem to under
Algebra ->
Quadratic Equations and Parabolas
-> SOLUTION: Solve by the elimination method.
0.05x+0.25y=11
0.15x+0.05=12
What is the solution of the system?
Again can someone explain how I am supposed to do this? I do not seem to under
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Question 137656: Solve by the elimination method.
0.05x+0.25y=11
0.15x+0.05=12
What is the solution of the system?
Again can someone explain how I am supposed to do this? I do not seem to understand anything that anyone has said. I am getting soooooo aggrevated. Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Solve by the elimination method.
0.05x+0.25y=11
0.15x+0.05y=12
What is the solution of the system?
:
Let's get rid of the decimals, multiply both equations by 100
5x + 25y = 1100
15x + 5y = 1200
:
Multiply the 1st equation by -3 and add to the 2nd equation
-15x - 75y = -3300
+15x + 5y = 1200
---------------------addition eliminates x; find y
0x - 70x = -2100
x =
x = +30
:
Find y using the equation; 5x + 25y = 1100, substitute 30 for x:
5(30) + 25y = 1100
150 + 25y = 1100
25y = 1100 - 150
25y = 950
y =
y = 38
:
:
Check solution in the 1st original equation, substitute for x and y:
.05(30) + .25(38) =
1.5 + 9.5 = 11; confirms out solutions
:
:
Was I able to make this understandable to you? Any questions?
