SOLUTION: Please solve. Thanks! 1.)y=(x+3)^2 2.)y=(x-4)^2

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Please solve. Thanks! 1.)y=(x+3)^2 2.)y=(x-4)^2      Log On


   

Question 137035: Please solve. Thanks!
1.)y=(x+3)^2
2.)y=(x-4)^2
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
y=(x+3)^2
y=x^2+6x+9
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y=(x-4)^2
y=x^2-8x+16 setting these 2 equation equal we get:
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x^2+6x+9=x^2-8x+16
x^2-x^2+6x+8x=16-9
14x=7
x=7/14
x=1/2 answer.
y=(1/2+3)^2
y=3.5^2
y=12.25 answer.
y=(1/2-4)^2
y=-3.5^2
y=12.25 answer.