SOLUTION: Write an equation of the line containing the given point and perpendicular to the given line. (3,-6);5x+2y=9 Can someone please help me with this.

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Write an equation of the line containing the given point and perpendicular to the given line. (3,-6);5x+2y=9 Can someone please help me with this.      Log On


   

Question 135885: Write an equation of the line containing the given point and perpendicular to the given line.
(3,-6);5x+2y=9
Can someone please help me with this.
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
5X+2Y=9
2Y=-5X+9
Y=-5X/2-9/2 (RED LINE) THIS LINE HAS A SLOPE OF -5/2 THEREFORE A PERPENDICULAR LINE HAS THE SLOPE=2/5.
-6=2/5*3=b
-6=6/5+b
b=-6-6/5
b=(-6*5-6)/5
b=(-30-6)/5
b=-36/5
SO THE EQUATION OF THIS LINE IS:
Y=2X/5-36/5. (GREEN LINE)
+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+-5x%2F2+-9%2F2%2C+2x%2F5+-36%2F5%29+ (graph 300x300 pixels, x from -10 to 10, y from -10 to 10, of TWO functions -5x/2 -9/2 and 2x/5 -36/5).