SOLUTION: Determine whether the following equations have a solution or not? Justify your answer. 4/3x2 - 2x + 3/4 = 0

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Determine whether the following equations have a solution or not? Justify your answer. 4/3x2 - 2x + 3/4 = 0       Log On


   

Question 132423: Determine whether the following equations have a solution or not? Justify your answer.
4/3x2 - 2x + 3/4 = 0

Found 2 solutions by edjones, checkley71:
Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
(4/3)x^2 - 2x + 3/4 = 0 I assume this is the problem.
a=4/3, b=-2, c=3/4
if the determinant, b^2-4ac is >=0, then it has a real solution.
b^2-4ac=4-4(4/3)(3/4)
=4-4=0
Because the determinant equals zero there is only one answer (0.75).
.
Ed
graph%28500%2C500%2C-10%2C10%2C-10%2C10%2C1.33333333x%5E2-2x%2B.75%29

Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
4/3x^2-2x+3/4
Using the quadratic equation:x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+ we get:
x=(2+-sqrt[-2*2-4*4/3*3/4])/(2*4/3)
x=(2+-sqrt4-4)/(8/3)
x=(2+-sqrt0)/(8/3)
x=2/(8/3)
x=2*3/8
x=6/8
x=3/4 answer.